题目: 题解:
class Solution:def countSegments(self, s):segment_count 0for i in range(len(s)):if (i 0 or s[i - 1] ) and s[i] ! :segment_count 1return segment_count
1.一般运算
加法
# gen x y z
df[x] df[y] df[z]减法
# gen x y - 1
df[x] df[y] - 1乘法
# gen var x * y
df[var] df[x] * df[y]除法
# gen x z / y
df[x] df[z] / df[y]取对数
# gen logx log(x)
df[logx] np.log(df[x])开根号
# gen z sqrt(y)
df[z] …